Answer:
0.02484 m
Explanation:
The depth of the pool increases due to thermal expansion. The change in volume is equal to the initial volume times the volumetric expansion coefficient times the change in temperature.
ΔV = V β ΔT
Assuming the cross section of the pool is constant:
AΔh = Ah β ΔT
Δh = h β ΔT
Plug in values:
Δh = (12.00 m) (207×10⁻⁶ K⁻¹) (10.00 °C)
Δh = 0.02484 m
