Respuesta :

To determine which reaction mixture will produce a precipitate, we need to consider the solubility rules for common ionic compounds: 1. Aqueous Na2CO3 and aqueous CuSO4: - When Na2CO3 reacts with CuSO4, the following double replacement reaction occurs: Na2CO3 + CuSO4 → Na2SO4 + CuCO3 - Copper(II) carbonate (CuCO3) is insoluble in water and will precipitate out of the solution, indicating that this mixture will produce a precipitate. 2. Dilute H2SO4 and aqueous NaOH: - When H2SO4 reacts with NaOH, the following neutralization reaction occurs: H2SO4 + 2NaOH → Na2SO4 + 2H2O - Sodium sulfate (Na2SO4) is soluble in water and will not form a precipitate, so this mixture will not produce a precipitate. 3. Dilute HNO3 and solid MgO: - Nitric acid (HNO3) reacting with magnesium oxide (MgO) will undergo an acid-base reaction: HNO3 + MgO → Mg(NO3)2 + H2O - Magnesium nitrate (Mg(NO3)2) is soluble in water, so no precipitate will form in this case. Therefore, the reaction mixture of aqueous Na2CO3 and aqueous CuSO4 will produce a precipitate (CuCO3), while the other two mixtures will not result in a precipitate formation.
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