Some units of length and its conversion that need to be recalled are:
[tex]1 ~ foot = 30.48 ~ cm[/tex]
[tex]1 ~ inch = 2.54 ~ cm[/tex]
[tex]1 ~ foot = 12 ~ inches[/tex]
[tex]1 ~ mile = 1609.34 ~ metres[/tex]
[tex]1 ~ yard = 0,9144 ~ metres[/tex]
[tex]1 ~\mu m = 1 \times 10^{-6} ~ m[/tex]
[tex]1 ~ US ~ liquid ~ gallon = 3.78541 ~ litres[/tex]
Some units of time and its conversion that need to be recalled are:
[tex]1 ~ month = 30 ~ days[/tex]
[tex]1 ~ day = 24 ~ hours[/tex]
[tex]1 ~ hour = 60 ~ minutes[/tex]
[tex]1 ~ minute = 60 ~ seconds[/tex]
Let us now tackle the problem !
Given:
[tex]12080 ~ \text{gallons/month} = \frac{12080 ~ \text{gallons}}{1 ~ \text{month}}[/tex]
[tex]12080 ~ \text{gallons/month} = \frac{12080 \times 3.78541 ~ \text{liters}}{1 \times 30 \times 24 ~ \text{hours}}[/tex]
[tex]12080 ~ \text{gallons/month} = \frac{45727.7528~ \text{liters}}{720 ~ \text{hours}}[/tex]
[tex]12080 ~ \text{gallons/month} \approx 63.511 ~ \text{liters/hour}[/tex]
Grade: High School
Subject: Mathematics
Chapter: Unit of Length and Time
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Microscope , Gallons , Month , Liters , Hour , Time
