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Phosphorus is obtained primarily from ores containing calcium phosphate. If a particular ore contains 35.1% calcium phosphate, what minimum mass of the ore must be processed to obtain 4.13 kg of phosphorus?

Respuesta :

scme1702
First, we determine the mass of calcium phosphate that is required. This is obtained by calculating the mass percentage of phosphorus in calcium phosphate, Ca₃(PO₄)₂

% Phosphorus = Mass of P x 100 / total mass
% Phosphorus = (31 * 2 * 100) / (310)
% P = 20%

The amount of calcium phosphate needed will be:

4.13 / 0.2 = 20.65 kg


Now, the ore has 35.1% calcium phosphate, so:

Mass of ore = mass of calcium phosphate required / percentage calcium phosphate

Mass of ore = 20.65 / 0.351

Mass of ore = 58.83 kg
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