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a baseball diamond is a square with sides of 90 feet. What is the shortest distance, to the nearest tenth of a foot, between first and third base?

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W0lf93
127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3

The shortest distance between the first and third base is 127.3 feet.

What is the shortest distance?

The shortest distance can be determined using Pythagoras theorem.

The Pythagoras theorem: a² + b² = c²

where:

a = length

b = base

c = hypotenuse

90² + 90²

8100 + 8100

= √16200 = 127.3 foot

To learn more about Pythagoras theorem, please check: https://brainly.com/question/14580675

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