Answer: Four ionic compounds formed will be [tex]Pb(NO_3)_4,Pb(HCO_3)_4,Pb(SO_3)_2\text{ and }Pb_3(PO_4)_4[/tex]
Explanation:
Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.
We are given:
One cation having formulas [tex]Pb^{4+}[/tex]
Four anions having formulas [tex]NO_3^-,HCO_3^-,SO_3^{2-}\text{ and }PO_4^{3-}[/tex]
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
The four ionic compounds are:
When lead ion and nitrate ions combine, it results in the formation of [tex]Pb(NO_3)_4[/tex] compound. This is named as lead (IV) nitrate.
When lead ion and bicarbonate ions combine, it results in the formation of [tex]Pb(HCO_3)_4[/tex] compound. This is named as lead (IV) hydrogen carbonate.
When lead ion and sulfite ions combine, it results in the formation of [tex]Pb(SO_3)_2[/tex] compound. This is named as lead (IV) sulfite.
When lead ion and phosphate ions combine, it results in the formation of [tex]Pb_3(PO_4)_4[/tex] compound. This is named as lead (IV) phosphate.
