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PLEASE HELP! 80 POINTS!

Sheila is flying a kite with 250 feet of her string let out. The angle the kite line makes with a line parallel to the ground is 45°. Sheila is 5 feet tall to her eye level.

What is the altitude of the kite?

Round the answer to the nearest whole number.



A.130 ft

B.177 ft

C.182 ft

D.222 ft

Respuesta :

ErikKuz
The altitude of the kite:
h = 5 + 250 · sin 45°
h = 5 + 250 · √2 / 2
h = 5 + 250 · 0.7071 = 5 + 176.77 = 181.77 ≈ 182 ft
Answer: The altitude is 183 ft.
M30W
The altitude of the kite:
h = 5 + 250 · sin 45°
h = 5 + 250 · √2 / 2
h = 5 + 250 · 0.7071 = 5 + 176.77 = 181.77 ≈ 182 ft
Answer: The altitude is 183 ft.

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