Answer:
Option D. line HJ
Step-by-step explanation:
Slope of line AB which passes through points A(-4, -2) and B(4, 2)
[tex]m1=\frac{2+2}{4+4}=\frac{4}{8}=1/2[/tex]
m1 = 1/2
Slope of line CD passing through C(-4, 0) and D(4, -4)
[tex]m2=\frac{0+4}{-4-4}=\frac{4}{(-8)}=-\frac{1}{2}[/tex]
m2 = -1/2
Slope of the line HJ passing through H(-1, 3) and J(1, -1)
[tex]m3 =\frac{-1-3}{1+1}=\frac{-4}{2}=(-2)[/tex]
m3 = (-2)
As we know that two line will be perpendicular if their m×m' = -1
Here we see that Line AB is having slope m1 = 1/2 and slope of HJ is m3 = (-2)
m1×m3 = (1/2)×(-2) = -1
Which clearly tells us that line HJ is perpendicular to line AB.
Therefore Option D. is the correct option.
