c(ad)+x=bd+ad(yz)
step 1:
first we separate x and y , so
x=bd+adyz-cad
Note: i) (yz) can be written as yz
ii) when the term cad comes to right side it becomes -cad, because it is with the addition operation in the left hand side. (it is a general rule of mathematics)
step 2: then we take out the common data from the above equation, so the common term for all terms in the right hand side is 'd',
so, x=d(b+ayz-ca)
step 3: now we need to find d, so
d =x/b+ayz-ca
Note: the term (b+ayz-ca) becomes the divisor of x since it is in the multiplication term on right hand side. so when moving it to left side, it becomes a division operator. (it is also a general rule of mathematics)
so d =x/b+ayz-ca
