Respuesta :
1 Solve for x in 1/3x+1/4y=1
X=3(1-y/4)
2 Substitute x=3(1-y/4) into 2x-3y=-30
6−9y/2 =−30
3 Solve for y in 6-9y/2=-30
y=8
4 Substitute y=8 into x=3(1-y/4)
x=−3
5 Therefore,
x=-3
y=8
X=3(1-y/4)
2 Substitute x=3(1-y/4) into 2x-3y=-30
6−9y/2 =−30
3 Solve for y in 6-9y/2=-30
y=8
4 Substitute y=8 into x=3(1-y/4)
x=−3
5 Therefore,
x=-3
y=8
Answer:
[tex]x=-3\\y=8[/tex]
Step-by-step explanation:
Given is a system of equations in two variables x and y as
[tex]\frac{x}{3} +\frac{y}{4} =1\\2x-3y =-30[/tex]
First we will remove the denominator in the equations by taking Lcd
Multiply I equation by 12
[tex]4x+3y =12...iii[/tex]
Add the second equation with iii equation
We get [tex]6x = -18x=-3[/tex]
Substitute in II equation
[tex]2(-3)-3y =-30\\y=8[/tex]
Solution set is
[tex]x=-3\\y=8[/tex]