light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to each other, what can you say about the light waves emerging from the second polarizer?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

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W0lf93 W0lf93 · Answer 1 · 2017-09-15T12:22:21+02:00

Indeed, this is one of the odd results in physics. A system of two polarizing filters arranged as shown below trasmits no light.

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Vespertilio Vespertilio · Answer 2 · 2019-05-20T08:46:35+02:00

Answer:

The intensity of light emerging from the second polarizer is zero.

Explanation:

The angle between the axis of first polarizer and the second polarizer is 90°.

According to the law of Malus

[tex]I = I_{0}\times Cos^{2}\Theta[/tex]

where, [tex]I_{0}[/tex] be the intensity of incident light on first polarizer and I be the intensity of light emerging out from second polarizer.

The intensity of light emerging out from first polarizer is given by

[tex]I_{1}=\frac{I_{0}}{2}[/tex]

the inetnsity of light emerging out from second polarizer is given by

[tex]I = I_{1}\times Cos^{2}90[/tex]

[tex]I = 0[/tex]

Thus, no light waves are emerging out from the second polarizer.