Respuesta :
I want to solve it in a simple way: let's combine the right side of the two equations together(since they are all equal to y) we could get:
[tex]- x^{2}-5x-4=-x^2+9x-18 [/tex], remove [tex]-x^2[/tex], we have:
[tex]14=14x[/tex], then we have: x=1
Then we have y = -1-5-4=-10, we could also test our result by put x=1, y=-10 into the second equation, and turns out the result is right.
[tex]- x^{2}-5x-4=-x^2+9x-18 [/tex], remove [tex]-x^2[/tex], we have:
[tex]14=14x[/tex], then we have: x=1
Then we have y = -1-5-4=-10, we could also test our result by put x=1, y=-10 into the second equation, and turns out the result is right.
The solution to the system of equation is as follows;
x = 1
y = -10
System of equations:
y = -x² - 5x - 4
y = -x² + 9x - 18
subtract equation(ii) from equation(i)
(-5x - 9x) + (-4 + 18) = 0
-14x + 14 = 0
-14x = -14
x = -14 / -14
x = 1
Therefore,
y = -x² - 5x - 4
y = -(1)² - 5(1) - 4
y = -1 - 5 - 4
y = -1 - 9
y = -10
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