First, multiply both sides by y to get rid of that y in the denominator. [tex] y(\frac{3}{2} y)= y( \frac{16}{y} + 2)
[/tex]
[tex] \frac{3}{2}y^2= 16+2y [/tex]
Then, rearrange it to put it into standard form so you can easily see the values for a, b, and c.
[tex]\frac{3}{2}y^2 +2y +16=0[/tex]
Plug into quadratic formula, and you get this result:
[tex]y= \frac{2+/- \sqrt{100} }{3} [/tex]
So, y=4, y=8/3
