Give the balanced chemical equation (including phases) that describes the combustion of butene, C4H8(g). Indicate the phases using abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Express your answer as a chemical equation.

Combustion reaction is the type of chemical reaction in which an organic compound undergoes reaction with oxygen gas to give carbon dioxide and water product.

When butene undergoes combustion reaction it gives carbon dioxide gas and water vapors as a product.

The chemical equation is given as:

[tex]C_4H_8+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)[/tex]

According to stoichiometry, 1 mole of butene gas reacts with 6 moles of oxygen gas to give 4 moles of carbon dioxide and 4 moles water vapors.

Eduard22sly Eduard22sly · Answer 2 · 2021-09-17T18:00:35+02:00

The balanced chemical equation that describes the combustion of butene, C₄H₈ is:

C₄H₈(g) + 6O₂(g) —> 4CO₂(g) + 4H₂O(g)

Chemical equation gives us a better understanding of chemical reaction as it represents a reaction using symbols and formula of the reactants and products involved in the reaction.

Combustion is a chemical reaction in which a compound reacts with oxygen to produce carbon (iv) oxide and water.

The equation for the combustion of butene, C₄H₈ is given below:

C₄H₈(g) + O₂(g) —> CO₂(g) + H₂O(g)

The above equation can be balance as follow:

C₄H₈(g) + O₂(g) —> CO₂(g) + H₂O(g)

There are 4 atoms of C on the left side and 1 atom on the right. It can be balance by writing 4 before CO₂ as shown below:

C₄H₈(g) + O₂(g) —> 4CO₂(g) + H₂O(g)

There are 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 4 before H₂O as shown below:

C₄H₈(g) + O₂(g) —> 4CO₂(g) + 4H₂O(g)

There are 2 atoms of O on the left side and a total of 12 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:

C₄H₈(g) + 6O₂(g) —> 4CO₂(g) + H₂O(g)

Therefore, the balanced equation for the combustion of butene, C₄H₈ is:

C₄H₈(g) + 6O₂(g) —> 4CO₂(g) + 4H₂O(g)

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