A 600 g
model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s
. The rocket engine, when it is fired, exerts a 8.0 N
vertical thrust on the rocket. Your goal is to have the rocket pass through a small horizontal hoop that is 20 m
above the launch point.

At what horizontal distance left of the hoop should you launch?

Respuesta :

Answer:

10.1 m

Explanation:

The rocket engine exerts a upwards vertical force on the rocket, and gravity exerts a downwards vertical force. From Newton's second law of motion, the net force on an object is equal to its mass times its acceleration. Once the vertical acceleration is found, we can use kinematics to find the time it takes the rocket to reach the hoop, and then find the horizontal distance traveled in that time.

Applying Newton's second law:

∑F = ma

F − mg = ma

8.0 N − (0.600 kg) (9.8 m/s²) = (0.600 kg) a

a = 3.53 m/s²

Given in the vertical direction:

s = 20 m

u = 0 m/s

a = 3.53 m/s²

Find: t

s = ut + ½ at²

20 = (0) t + ½ (3.53) t²

t = 3.36 s

Given in the horizontal direction:

u = 3.0 m/s

a = 0 m/s²

t = 3.36 s

Find: s

s = ut + ½ at²

s = (3.0) (3.36) + ½ (0) (3.36)²

s = 10.1 m

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