Answer:
In this problem, we should use a measure of center to ensure that each student receives the same number of candies. Specifically, we would want to calculate the average number of candies per bag and then distribute bags accordingly to ensure equality among students.
As for the choice between plain M&Ms and peanut M&Ms, it doesn't matter which type of M&Ms we use if our goal is to ensure that each student gets the same number of candies. The critical factor is that we distribute the bags equally, regardless of the contents. So, whether it's plain M&Ms or peanut M&Ms, as long as each bag contains the same number of candies, we can use a measure of center, such as the mean or median, to determine how many bags each student should receive to achieve equality in distribution.
