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An 8,500 kg car is moving along a smooth horizontal surface at a constant speed and has
10.000 kJ of energy (kinetic). There is 5000 N of frictional force opposing
the forward
motion of the car. The car runs out of gas. Assuming the frictional force remains consta
will it reach the gas station that is half a kilometer away before it comes
to a stop?

Respuesta :

Answer:

Yes, it will reach the gas station.

Explanation:

The kinetic energy of an object is equal to half its mass times the square of its speed. Given the kinetic energy and mass, the initial speed of the car can be found. Afterward, two methods can be used to find the distance traveled by the car while decelerating. Method 1: the work-energy theorem says that the work done is equal to the change in kinetic energy. Method 2: Newton's second law of motion says that the net force on the car is equal to its mass times acceleration; the distance traveled can then be found with kinematics.

Initial speed

First, use the kinetic energy to find the initial speed.

KE = ½ mv²

where m is mass and v is speed.

Given:

KE = 10,000 kJ = 10,000,000 J

m = 8500 kg

Find: v

10,000,000 J = ½ (8500 kg) v²

v = 48.5 m/s

Method 1: Work-energy

The distance the car travels can be found with work-energy theorem.

W = ΔKE

W = KE − KE₀

The car comes to a stop, so its final kinetic energy is zero. The work done by friction is equal to the force times the distance.

Fd = 0 − KE₀

(-5000 N) d = -10,000,000 J

d = 2000 m

Method 2: Force and kinematics

The distance traveled can also be found using Newton's second law and kinematics.

F = ma

-5000 N = (8500 kg) a

a = -0.588 m/s²

v² = u² + 2as

(0 m/s)² = (48.5 m/s)² + 2 (-0.588 m/s²) s

s = 2000 m

Answer

The car travels 2000 meters, or 2 km. It will easily be able to reach the gas station.

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