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(a)
What is the maximum torque (in N·m) on a 175 turn square loop of wire 18.0 cm on a side that carries a 52.0 A current in a 1.60 T field?
(b)
What is the torque (in N·m) when is 10.9°?

Respuesta :

To calculate the torque on a current-wearing square loop in a magnetic field, you may use the components:

[ textTorque = N cdot I cdot A cdot B cdot sin(theta) ]

wherein:
- ( N ) is the range of turns within the loop (one hundred seventy five turns),
- ( I ) is the modern-day flowing via the loop (fifty two.Zero A),
- ( A ) is the location of the loop ((18.0 , textcm times 18.Zero , textual contentcm)),
- ( B ) is the magnetic subject electricity (1.60 T),
- ( theta ) is the angle between the ordinary to the loop and the magnetic field.

(a) To discover the maximum torque:

[ A = 18.0 , textcm times 18.0 , textcm = 0.18 , textm times 0.18 , textm = 0.0324 , textm^2 ]

[ textTorque = 175 times 52.0 times 0.0324 times 1.60 times sin(90°) ]

[ textTorque = 175 times 52.0 times 0.0324 times 1.60 = textanswer ]

(b) To discover the torque at an perspective of 10.Nine°:

[ textTorque = 175 times 52.0 times 0.0324 times 1.60 times sin(10.9°) ]

[ textTorque = 175 times 52.0 times 0.0324 times 1.60 times sin(10.9°) = textanswer ]

Calculating those values will give you the torque in Newton-meters.

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