Which is the equation for the circle with center (6, 2) and radius 8?
a. (x + 6)² (y + 2)² = 64
b. (x – 6)² (y – 2)² = 64
c. (x – 6)² – (y – 2)² = 64
d. (x – 6)² (y – 2)² = 8

Respuesta :

Answer:

[tex](x-6)^2+(y-2)^2=64[/tex]

Step-by-step explanation:

The equation for a circle using the Cartesian coordinate system is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where:

  • [tex](h,k)[/tex] is the center of the circle
  • [tex]r[/tex] is the circle's radius

We are given:

  • [tex](h,k) = (6,2)[/tex]     ⇒     [tex]h=6[/tex],   [tex]k=2[/tex]
  • [tex]r=8[/tex]                 ⇒     [tex]r^2 = 64[/tex]

Thus, the equation that models the given circle is:

B) [tex]\boxed{(x-6)^2+(y-2)^2=64}[/tex]

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