Answer:
1.88 J
Explanation:
The elastic potential energy stored in a spring is half the spring stiffness times the square of the displacement. From Hooke's law, the force to stretch a spring is the product of the spring stiffness and the displacement. Using these two equations, we can solve for the elastic energy.
Solving Hooke's law for displacement:
F = kx
x = F / k
Substituting this into the elastic energy equation:
EE = ½ kx²
EE = ½ k (F / k)²
EE = ½ F² / k
EE = ½ (75 N)² / (1500 N/m)
EE = 1.88 Nm
The elastic potential energy stored in the spring is 1.88 J.
