Respuesta :
Answer:
To solve the equation, let's simplify and rearrange the terms:
c + 13c + 9 + c^2c + 6 = 34c + 12
Combining like terms:
c^2c + 14c + 15 + c^2c + 6 = 34c + 12
2c^2 + 14c + 21 = 34c + 12
Next, let's bring all the terms to one side of the equation:
2c^2 + 14c - 34c + 21 - 12 = 0
2c^2 - 20c + 9 = 0
Now, we can solve this quadratic equation. However, this equation does not factor easily. So, we can use the quadratic formula:
c = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 2, b = -20, and c = 9. Plugging these values into the quadratic formula:
c = (-(-20) ± √((-20)^2 - 4 * 2 * 9)) / (2 * 2)
c = (20 ± √(400 - 72)) / 4
c = (20 ± √328) / 4
c = (20 ± 18.11) / 4
This gives us two possible solutions:
c = (20 + 18.11) / 4 ≈ 9.53
c = (20 - 18.11) / 4 ≈ 0.47
Therefore, the solutions to the equation are approximately c = 9.53 and c = 0.47.
