a worker drives 0.500 kg spike into a rail tie with a 2.50 kg sledgehammer the hammer hits the spike with a speed of 65.0.m/s if 1/3 of the hammers kinetic energy is converted to internal energy of the hammer and spike. How much does the total internal energy increase?

Respuesta :

Answer:

17,600 J

Explanation:

From the problem statement, the increase in the internal energy is equal to one third of the sledgehammer's initial kinetic energy. The kinetic energy of an object is equal to half its mass times the square of its speed. By finding the sledgehammer's kinetic energy, we can find the increase in internal energy.

The hammer's kinetic energy is:

KE = ½ mv²

KE = ½ (2.50 kg) (65.0 m/s)²

KE = 52,812.5 J

The increase in internal energy is:

ΔE = ⅓ KE

ΔE = ⅓ (52,812.5 J)

ΔE = 17,600 J

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