Answer:
[tex]\sf B.\quad \Large\text{$\left(-1\frac15,4\frac35\right)$}[/tex]
Step-by-step explanation:
The exact solution to a graphed system of linear equations is the point of intersection of the two lines.
To find the solution of the graphed system of equations, first find the equation of each line by entering its slope and y-intercept into the slope-intercept form of a linear equation:
[tex]\boxed{\begin{array}{l}\underline{\textsf{Slope-intercept form of a linear equation}}\\\\y=mx+b\\\\\textsf{where:}\\\phantom{ww}\bullet\;\;\textsf{$m$ is the slope.}\\\phantom{ww}\bullet\;\;\textsf{$b$ is the $y$-intercept.}\\\end{array}}[/tex]
The line with the positive slope crosses the y-axis at y = 7 and has a slope of 2, since the y-values increase by 2 units for every 1 unit increase in x-values. Therefore, the equation of this line is:
[tex]y = 2x + 7[/tex]
The line with the negative slope crosses the y-axis at y = 1 and has a slope of -3, since the y-values decrease by 3 units for every 1 unit increase in x-values. Therefore, the equation of this line is:
[tex]y=-3x+1[/tex]
To find the x-coordinate of the point of intersection, substitute the first equation into the second equation and solve for x:
[tex]2x+7=-3x+1\\\\\\5x=-6\\\\\\x=-\dfrac{6}{5}\\\\\\x=-1\frac15[/tex]
Now, substitute x = -6/5 into one of the equations and solve for y. Let's use y = 2x + 7:
[tex]y = 2\left(-\dfrac{6}{5}\right)+ 7\\\\\\y = \dfrac{-12}{5}+\dfrac{35}{5}\\\\\\y=\dfrac{23}{5}\\\\\\y=4\frac35[/tex]
Therefore, the exact solution to the graphed system of equations is:
[tex]\Large\text{$\left(-1\frac15,4\frac35\right)$}[/tex]