A body falling from a high tower travels 40m in the last 2.71s of it's fal to the ground. The height of the tower(in meteres) is (take g=10m/s²)​

Respuesta :

Answer:

40.1 m

Explanation:

Objects in free fall, or projectiles, undergo constant acceleration. Using kinematics, we can write equations that relate the displacement, velocity, acceleration, and time. One kinematic equation is:

s = ut + ½ at²

where s is displacement, u is initial velocity, a is acceleration, and t is time. Since the initial velocity is zero, this simplifies to:

s = ½ at²

If h is the height of the tower, and t is the total time it takes to fall, and the acceleration is a = 10 m/s², then:

h = 5t²

Similarly, the body falls a distance of h − 40 meters in the first t − 2.71 seconds, so we can write a second equation:

h − 40 = 5 (t − 2.71)²

Substituting and solving for time:

5t² − 40 = 5 (t − 2.71)²

t² − 8 = (t − 2.71)²

t² − 8 = t² − 5.42 t + 7.34

0 = -5.42 t + 15.34

t = 2.83

Therefore, the height of the tower is:

h = 5t²

h = 5 (2.83)²

h = 40.1

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