A man is six times as old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born. ​

Respuesta :

Answer:

The man was 25 years old when his son was born

Step-by-step explanation:

Let's start by assigning variables to represent the ages of the man and his son.

Let M represent the current age of the man.

Let S represent the current age of the son.

From the given information, we have two equations:

1. "A man is six times as old as his son." This can be represented as:

  M = 6S

2. "Twenty years later, the man will be twice as old as his son." This can be represented as:

  (M + 20) = 2(S + 20)

Now, we can solve these equations simultaneously to find the values of M and S.

First, let's solve equation 1 for M in terms of S:

M = 6S

Now, substitute this expression for M into equation 2:

(6S + 20) = 2(S + 20)

Expand and solve for S:

6S + 20 = 2S + 40

6S - 2S = 40 - 20

4S = 20

S = 5

Now that we have found the current age of the son (S = 5), we can use equation 1 to find the current age of the man:

M = 6S

M = 6(5

M = 30

So, the current age of the man is 30 years.

To find the age of the man when his son was born, we subtract the son's current age (5) from the man's current age (30):

30 - 5 = 25

Therefore, the man was 25 years old when his son was born.

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