A baseball is thrown from a horizontal plane following a parabolic path with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. How far from the throwing point will the ball attain its original level?

Respuesta :

Answer:

883.7 m

Explanation:

The baseball is in free fall. Neglecting air resistance, projectiles can be modeled using constant acceleration in both the horizontal and vertical direction. The kinematic equation that applies is:

s = ut + ½ at²

where s is the displacement, u is the initial velocity, a is the acceleration, and t is time.

First, find the time it takes the ball to land. In the y direction, the displacement is zero, since the ball returns to its original level, and the acceleration is the acceleration due to gravity.

s = 0 m

u = 100 sin 30 = 50 m/s

a = -9.8 m/s²

Find: t

s = ut + ½ at²

0 = 50t + ½ (-9.8) t²

0 = 50t − 4.9 t²

0 = 50 − 4.9 t

t = 10.2

Next, in the x direction, the acceleration is zero, since there's no forces acting on the ball in the horizontal direction.

u = 100 cos 30 = 86.6 m/s

a = 0 m/s²

t = 10.2 s

Find: s

s = ut + ½ at²

s = (86.6) (10.2) + ½ (0) (10.2)²

s = 883.7

Therefore, the ball will land approximately 884 meters away from the throwing point.

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