Answer:
Hi.
Explanation:
Certainly! Let's break down the problem and find the minimum number of moves the students need to perform in order to get a word of minimal length.
Given the string `word` consisting of lowercase English letters, the students can perform the following operation:
1. Choose any index `i`.
2. Let the character at that index be `c`.
3. Delete the first occurrence of `c` to the left of index `i`, and the first occurrence of `c` to the right of index `i` (even if either the left or right occurrence doesn't exist).
For example, consider the word `"adabacaea"`. If we choose index 4 (0-based), the first occurrence of `'a'` to the left (at index 2) and the first occurrence of `'a'` to the right (at index 6) are deleted, resulting in the word `"adbacea"`.
To find the minimum number of moves, we need to iteratively choose indices and perform the deletion operation until the word cannot be reduced further.
Let's illustrate this with the given example:
1. **Choose index 0**: `"baabacaa"`. Delete the `'b'` to its right at index 3. There is no `'b'` to its left, so the operation is finished. Word becomes `"baaacaa"`.
2. **Choose index 2**: `"baaacaa"`. Delete the `'a'` to its right at index 3. Word becomes `"bacaa"`.
3. **Choose index 3**: `"bacaa"`. Delete the `'c'` to its left at index 1. Word becomes `"bca"`.
The word cannot be reduced further, and the answer is **3**.
Now, let's implement the `getMinimumMoves` function to find the minimum moves for any given word.
