A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the
wall over the course of the collision.
What is the magnitude of the velocity, or final speed, of the car after the collision?

The impulse imparted on the car by the wall is equal to the car's change in momentum. The impulse can be found by finding the area under the force vs time graph.

Impulse = area under the curve. Dividing the area into triangles and trapezoids, the impulse is:

J = ½ (4 N) (0.02 s) + ½ (4 N + 5 N) (0.02 s) + ½ (5 N + 4 N) (0.04 s) + ½ (4 N) (0.04 s)

J = 0.390 Ns

Impulse = change in momentum. Taking towards the wall to be negative and away from the wall to be positive, the impulse will be positive and the initial velocity will be negative.

J = Δp

J = mΔv

J = m (v − u)

0.390 Ns = (0.300 kg) (v − -0.820 m/s)

v = 0.480 m/s

A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the wall over the course of the collision. What is the magnitude of the velocity, or final speed, of the car after the collision?

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A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the
wall over the course of the collision.
What is the magnitude of the velocity, or final speed, of the car after the collision?