Answer:
cosH = 4/[tex]\sqrt{20}[/tex]
in simplest form
= 4/sqrt(20)
= 4/sqrt(4*5)
=4/(2*sqrt(5))
=2/sqrt(5)
= [tex]\frac{2}{\sqrt{5}}[/tex]
or if you are taught to rationalize the denominator the simpliest may also be
= (2/sqrt(5)) * (sqrt(5)/sqrt(5))
=(2*sqrt(5))/5
=[tex]\frac{2\sqrt{5} }{5}[/tex]
Step-by-step explanation:
SOACAHTOA states the non 90 degree angle (J or H in this context) in a right angle triangle is equal to Adjacent over Hypotenuse so cos(H) = 4/[tex]\sqrt{20}[/tex]
From soaCAHtoa
C(cos)A(adjacent)H(Hypotenuse)
Remember that the Hypotenuse is always the longest edge opposite to the 90 degree angle. The Hypotenuse can never be the Adjacent or Opposite edge in the context of SOACAHTOA.
