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The diagrams shows a 20-kilogram mass at rest on a frictionless inclined plane with a 60° incline.

What is the magnitude of the force, F, to the nearest tenth?
Responses
A 98.0 N
B 169.7 N
C 196.0 N
D 339.5 N

The diagrams shows a 20kilogram mass at rest on a frictionless inclined plane with a 60 incline What is the magnitude of the force F to the nearest tenth Respon class=

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lubug2009

Answer:  B 169.7 N

Explanation: The force, F, required to keep the 20-kg mass at rest on the inclined plane can be calculated using F = m*g*sinθ, where m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of inclination (60° in this case).

F = 20 kg * 9.8 m/s^2 * sin(60°)

F = 20 * 9.8 * 0.866 (sin(60°) = 0.866)

F ≈ 169.7 N

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