Respuesta :
Answer:
973.69 liters
Explanation:
To solve this problem, we can use the combined gas law, which states:
\[ \frac{{P_1 \times V_1}}{{T_1}} = \frac{{P_2 \times V_2}}{{T_2}} \]
Where:
- \( P_1 \) and \( T_1 \) are the initial pressure and temperature,
- \( V_1 \) is the initial volume,
- \( P_2 \) and \( T_2 \) are the final pressure and temperature, and
- \( V_2 \) is the final volume.
Given:
- Initial volume (\( V_1 \)): 893 L
- Initial temperature (\( T_1 \)): -35°C (convert to Kelvin: 238 K)
- Initial pressure (\( P_1 \)): 855 kPa
- Final temperature (\( T_2 \)): 0°C (convert to Kelvin: 273 K)
- Final pressure (\( P_2 \)): 1 kPa
Now, we'll plug in the values into the combined gas law equation:
\[ \frac{{855 \times 893}}{{238}} = \frac{{1 \times V_2}}{{273}} \]
Solving for \( V_2 \):
\[ V_2 = \frac{{(855 \times 893 \times 273)}}{{(238 \times 1)}} \]
\[ V_2 ≈ 973.69 \, \text{L} \]
So, the volume of the gas sample at 0°C and 1 kPa would be approximately 973.69 liters.
