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A ray of light of wavelength 600 nm is incident in water (refractive index = 4/3) on the water-air interface at an angle less than the critical angle. What is the wavelength associated with the refracted ray?​

Respuesta :

Answer:

The refracted wavelength = 450 nm.

Explanation:

When a ray of light goes from 1 medium to another medium with different refractive index, the frequency will be constant but the wavelength will change:

[tex]\boxed{n_1\cdot \lambda_1=n_2\cdot \lambda_2}[/tex]

where:

  • n₁ = refractive index of the 1st medium
  • λ₁ = wavelength of ray before refraction
  • n₂ = refractive index of the 2nd medium
  • λ₂ = wavelength of ray after refraction

Given:

  • n₁ = 600 nm
  • λ₁ = 1 (we normally take n = 1 for air)
  • n₂ = 4/3

[tex]n_1\cdot \lambda_1=n_2\cdot \lambda_2[/tex]

[tex]1(600)=\frac{4}{3} \lambda_2[/tex]

[tex]\lambda_2=600\times\frac{3}{4}[/tex]

    [tex]=450\ nm[/tex]

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