Admissions to a baseball game is $3.50 for general admission and $6.00 for reserved seats. The receipts were $4423.00 for 1048 paid admissions. How many of each ticket were sold ?

Let x equal the number of general admission tickets sold, and y equal the number of reserved seat tickets sold. We can create a system of equations from the given information.

Because the total number of tickets sold is 1048, we can make the equation:

[tex]x + y = 1048[/tex].

We know that a total of $4423.00 was generated, and the price of each ticket, so we can also form the following equation:

[tex]3.50x + 6.00 y = 4423.00[/tex].

We can solve the system of equations by multiplying the entire first equation by 6. Then, we will reuse the second equation.

[tex]6x+6y=6288[/tex]

[tex]3.50x + 6y = 4423[/tex]

Next, we subtract the two equations from each other.

[tex]2.50x = 6288-4423 = 1865[/tex]

[tex]x = \frac{1865}{2.5} = 746[/tex]

Now we know that 746 general admission tickets were sold. Plug it back into the first equation that we made( x + y = 1048 ) to find the number of reserved seat tickets sold.

[tex]746+y=1048[/tex][tex]y=1048-746=302[/tex]

Thus, the final answer is 746 general admission tickets and 302 reserved seat tickets sold.