The balanced chemical equation for the combustion of benzene (C6H6) with oxygen (O2) is:
C6H6 + 15/2 O2 → 6 CO2 + 3 H2O
This equation shows that 1 mole of benzene reacts with 15/2 moles of oxygen to produce 6 moles of carbon dioxide and 3 moles of water.
To find out how many moles of benzene are needed to burn 8.05 moles of oxygen, we can use the stoichiometry of the reaction:
8.05 moles O2 × (1 mole C6H6 / (15/2) moles O2) = 8.05 × (2/15) moles C6H6
= 1.07333... moles C6H6
So, approximately 1.07 moles of benzene are needed to burn 8.05 moles of oxygen.
