Answer:
[tex]\text{no solution}[/tex]
Step-by-step explanation:
[tex]\text{Solution: }\\2x+3y=2\\\\\text{or, }x=\dfrac{2-3y}{2}.....(1)[/tex]
[tex]4x+6y=6\\\text{Substituting value of }x\text{ from equation(1),}\\\\4\bigg(\dfrac{2-3y}{2}\bigg)+6y=6\\\\\text{or, }2(2-3y)+6y=6\\\text{or, }4-6y+6y=6\\\text{or, }4=6\ \ \ [\text{Invalid}][/tex]
[tex]\text{This statement is inconsistent, indicating there are no solutions that }\\\text{satisfy both equations simultaneously. }[/tex]
