Answer:
4 KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g) In the reaction, 4 moles of KO2 react with 2 moles of H2O 1 mole of KO2 will react with 2 4 2 4 moles of H2O 0.15 moles of KO2 will react with 2 4 2 4 × 0.15 moles of H2O = 0.075 moles of H2O But we have 0.10 moles of H2O ∴ ∴ KO2 is the limting reagent. Again. According to reaction. 4 moles of KO2 produces 3 moles of O2 0.15 moles of KO2 will produce = 3 4 3 4 x 0.15 moles of O2 = 0.1125 moles of O2.Read more on Sarthaks.com - https://www.sarthaks.com/1007711/potassium-superoxide-ko2-is-used-in-rebreathing-gas-masks-to-generate-oxygen
