Two jet aeroplanes fly on parallel courses which are 12 km apart. Their air speeds are 200m/s^2 and 250m/s^2 respectively. How fast is the distance between them changing at the instant when the slower jet is 5 km ahead of the faster one?

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Answer:

this is the answer

Step-by-step explanation:

To solve this related rates problem, we can use the Pythagorean theorem. Let \( x \) be the distance traveled by the slower jet, and \( y \) be the distance between the jets. Then, \( y = \sqrt{12^2 + x^2} \).

Now, differentiate both sides of the equation with respect to time:

\[ \frac{dy}{dt} = \frac{1}{2\sqrt{12^2 + x^2}} \cdot 2x \frac{dx}{dt} \]

Given that the slower jet is 5 km ahead, when \( x = 5 \) km, we can substitute this into the equation along with the given values for \( \frac{dx}{dt} \) and \( x \) to find \( \frac{dy}{dt} \).

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