Measurements of the parallel sides are 4m , 6m.
Step-by-step explanation:
[tex]\boxed{\text{\bf Area of trapezium =$\bf \dfrac{(a + b)*h}{2}$}}[/tex]
Here, a and b are the measurements of the parallel sides.
h denotes height. h = 6 m
Area = 30 square m
It is given that the difference in the measurements of parallel sides is 2m.
If we take measure of one parallel side is 'x', then the measure of the other parallel side = x +2
a = x and b = x +2
[tex]\sf \dfrac{(x + x + 2)*6}{2}= 30\\\\\\ \dfrac{(2x +2)*6}{2}=30[/tex]
(2x + 2)*3 =30
Divide both sides by 3,
2x + 2 = 30 ÷ 3
2x + 2 = 10
Subtract 2 from both sides,
2x = 10 - 2
2x = 8
Divide both sides by 2,
x = 8 ÷ 2
x = 4
a = 4 m
b = x + 2
= 4 + 2
= 6 m
Measurements of the parallel sides are 4m, 6m.
