Respuesta :
The answer is f(x)=x^2+2x-5
A quadratic formula must have at least one square (x^2) and cannot have higher exponents.
The reason 0x^2 doesn't count is because that will always equal zero no matter the value of x, which makes that term a constant.
A quadratic formula must have at least one square (x^2) and cannot have higher exponents.
The reason 0x^2 doesn't count is because that will always equal zero no matter the value of x, which makes that term a constant.
Answer: The correct answer is [tex]f(x)=x^2+2x-5[/tex]
Step-by-step explanation:
A Quadratic equation is defined as the equation in which the highest power of the variable is 2. The general form of this equation represents:
[tex]ax^2+bx+c=0[/tex]
where, [tex]a\neq 0[/tex]
From the given options:
1. [tex]f(x)=-8x^3-16x^2-4x[/tex]: Here, the highest power of the variable is 3. Therefore, it is not a quadratic equation.
2. [tex]f(x)=x^2+2x-5[/tex]: Here, the highest power of the variable is 2. Therefore, it is a quadratic equation.
3. [tex]f(x)=+1[/tex]: Here, the highest power of the variable is 0. Therefore, it is not a quadratic equation.
4. [tex]f(x)=0x^2-9x+7[/tex]: Here, the highest power of the variable is 1. Therefore, it is not a quadratic equation.
Hence, the correct answer is [tex]f(x)=x^2+2x-5[/tex]