Respuesta :

The answer is f(x)=x^2+2x-5
A quadratic formula must have at least one square (x^2) and cannot have higher exponents.
The reason 0x^2 doesn't count is because that will always equal zero no matter the value of x, which makes that term a constant.

Answer: The correct answer is [tex]f(x)=x^2+2x-5[/tex]

Step-by-step explanation:

A Quadratic equation is defined as the equation in which the highest power of the variable is 2. The general form of this equation represents:

[tex]ax^2+bx+c=0[/tex]

where, [tex]a\neq 0[/tex]

From the given options:

1. [tex]f(x)=-8x^3-16x^2-4x[/tex]: Here, the highest power of the variable is 3. Therefore, it is not a quadratic equation.

2. [tex]f(x)=x^2+2x-5[/tex]: Here, the highest power of the variable is 2. Therefore, it is a quadratic equation.

3. [tex]f(x)=+1[/tex]: Here, the highest power of the variable is 0. Therefore, it is not a quadratic equation.

4. [tex]f(x)=0x^2-9x+7[/tex]: Here, the highest power of the variable is 1. Therefore, it is not a quadratic equation.

Hence, the correct answer is [tex]f(x)=x^2+2x-5[/tex]

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