f(x)=(x+1)^-1
f(x)=1/(x+1) so
f(x)/g(x) is
1/[(x+1)(x-2)]
Since division by zero approaches infinity, it is not a real value, and is said to be undefined. Division by zero is "not allowed", which just really means that it does not have a real value. So in this case x cannot equal -1 or 2 so the domain is:
All real numbers except -1 or 2...which can be expressed as:
(-oo,-1),(-1,2),(2,+oo)
