Answer:
The given equation is in the form (y = 3(x+1)^2 - 5). By comparing it with the standard vertex form of a parabola, (y = a(x-h)^2 + k), we can identify the coordinates of the vertex as ((h, k)), where (h = -1) and (k = -5). Therefore, the coordinates of the vertex for the given parabola are ((-1, -5)).
Step-by-step explanation:
