Respuesta :
The ions present in the solution of Na₃PO₄ are:
3Na⁺¹ and 1PO₄⁻³
there are 3 sodium ions (Na⁺¹) are present, these are cations (+).
And 1 phosphate ion (PO₄⁻³) is present, this is anion (-),
When these cations and ions meet together a compound is formed, in this case 3 sodium ions make a bond with 3 oxygens of phosphate and makes a compound of sodium phosphate.
3Na⁺¹ and 1PO₄⁻³
there are 3 sodium ions (Na⁺¹) are present, these are cations (+).
And 1 phosphate ion (PO₄⁻³) is present, this is anion (-),
When these cations and ions meet together a compound is formed, in this case 3 sodium ions make a bond with 3 oxygens of phosphate and makes a compound of sodium phosphate.
The ions present in the solution of [tex]\rm Na_3PO_4[/tex] will be [tex]\rm Na^+\,,\;PO_4^-\;,\;H_2PO_4^-\;,\;HPO_4^2^-[/tex].
The solution of [tex]\rm Na_3PO_4[/tex] will results in the dissociation of the molecule.
The dissociation will be:
[tex]\rm Na_3PO_4\;\rightarrow\;3\;Na_+\;+\;PO_4^-[/tex]
Thus the dissociation will result in the 3 sodium ions and 1 phosphate ion. The phosphate ion in the water solution will form phosphonium ions as well.
Thus the ions in the solution will be:
[tex]\rm Na^+\,,\;PO_4^-\;,\;H_2PO_4^-\;,\;HPO_4^2^-[/tex].
For more information about ions in a solution, refer to the link:
https://brainly.com/question/491778
