The triangle 30°-60°-90° is a special triangle.
Whatever the length of the hypotenuse is, the length of the side opposite to the angle with measure  30° is half of the length of the side opposite 60°.
In our triangle, the sides are x-2x-16
We can apply the Pythagorean theorem:
[tex]16^{2}= x^{2} +(2x)^{2} [/tex]
[tex]16^{2}= 5x^{2} [/tex]
[tex] x^{2} = \frac{16^{2} }{5}= \frac{16^{2} }{ ( \sqrt{5} )^{2}}= (\frac{16}{ \sqrt{5}})^{2} [/tex]
so x=[tex] \frac{16}{ \sqrt{5} }= 7.16[/tex] (cm)
the length of the other leg is 2x =14.32 (cm)
Answer: 7.16, 14.32
