Below is the solution of assign true to is_prime if n has no factors other than 1 and itself.
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Given a positive integer n, assign true to is_prime if n has no factors other than 1 and itself. And remember, m is a factor of n if m divides n evenly. So:
if n == 2:
is_prime = True
elif n % 2 == 0:
is_prime = False
else:
is_prime = True
for m in range (3, int(n**0.5)+1, 2):
if n % m == 0:
is_prime = False
Grade: 9
Subject: mathematics
Chapter: python
Keywords: python, integer, factors, python IDLE, is_prime
