Respuesta :
The mean of the first set of 7 numbers is 20.
Therefore the sum of the 7 numbers is
S₁ = 7*20 = 140
The mean of the second set of 13 numbers is 40.
Therefore the sum of the 13 numbers is
S₂ = 13*40 = 520
The sum of the two sets of numbers is
S = S₁ + S₂ = 140 + 520 = 660
Altogether, there are 7+13 = 20 numbers.
The overall mean of the 20 numbers is
660/20 = 33
Answer: The mean of all 20 numbers is 33.
Therefore the sum of the 7 numbers is
S₁ = 7*20 = 140
The mean of the second set of 13 numbers is 40.
Therefore the sum of the 13 numbers is
S₂ = 13*40 = 520
The sum of the two sets of numbers is
S = S₁ + S₂ = 140 + 520 = 660
Altogether, there are 7+13 = 20 numbers.
The overall mean of the 20 numbers is
660/20 = 33
Answer: The mean of all 20 numbers is 33.
Using the weighed mean, it is found that the mean of all 20 numbers is of 33.
What is the weighed mean?
The weighed mean is given by the sum of all elements in a data-set multiplied by it's weight, divided by the sum of the weights.
In this problem, the means are divided as follows.
- Mean of 20 with a weight of 7.
- Mean of 40 with a weight of 13.
Hence:
[tex]M = \frac{20(7) + 40(13)}{20} = 33[/tex]
The mean of all 20 numbers is of 33.
More can be learned about the weighed mean at https://brainly.com/question/24398353
