[tex] solution 1[/tex] → [tex]x + y = 10[/tex]
[tex]solution 2[/tex] →[tex] y = (-x) + 10 [/tex]
[tex]1) x + y = 10 [/tex]
The '[tex]x
[/tex]' in the second solution becomes a positive
[tex]2) x + y = 10[/tex]
Change the "[tex]x [/tex]" back to a negative
So, [tex]y = (-x) + 10 [/tex]
[tex]1) (part 1)[/tex]: [tex]x + ( (-x) + 10 = 10 [/tex]
[tex]1) (part 2)[/tex]: [tex]0 = 0 [/tex]
[tex]This [/tex] [tex]problem [/tex] [tex]has [/tex] [tex]many/infinite[/tex] [tex]number
[/tex] [tex]of[/tex] [tex]Solutions![/tex]
[tex]Good Luck [/tex] [tex]On Your [/tex] [tex]Assignment![/tex]
