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∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?

Respuesta :

as the angles are complementary sin A = cos B and  sin B = cos A

so sin A + sin B =  0.55 + 0.83 =  1.38
calculista

Answer:

[tex]sin(A)+sin(B)=1.38[/tex]

Step-by-step explanation:

Let

A, B and [tex]90\°[/tex] the measures of the angles in a right triangle

we know that

[tex]m<A+m<B=90\°[/tex] ------> by complementary angles

so

[tex]sin(A)=cos(B)[/tex]

[tex]sin(B)=cos(A)[/tex]

In this problem we have

[tex]cos(A)=0.83[/tex]

[tex]cos(B)=0.55[/tex]

therefore

[tex]sin(A)=0.55[/tex]

[tex]sin(B)=0.83[/tex]

[tex]sin(A)+sin(B)=0.55+0.83=1.38[/tex]

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