-x+y=5; 4x+y=10 .
Part A: Use substitution to find the solution to the systems of equations. Include all of your work in your final answer.
Part B: Algebraically verify your answer to Part A. Include all of your work in your final answer.
Part A: -x+y=5       +x   +x        y=x+5 4x+x+5=10 5x+5=10    -5  -5 5x=5 x=1 1(-x) +y=5 -1+y=5 +1   +1 y=6 The solution is (1,6) Part B: -x+y=5 -1+6=5 5=5 4x+y=10 4(1)+6=10 4+6=10 10=10
