Respuesta :
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
The easiest way to solve problems with consecutive integers is set the first as:
1st number =( x-1)
2nd number = x
3rd number = (x+1) [since all are consecutive)
(x-1) + x + (x+1) = 108
3x = 108
x = 36
Obviously you could have set x. the 1st; x+1 the 2nd & x+2 the 3rd & you would reach the same result x =36
1st number =( x-1)
2nd number = x
3rd number = (x+1) [since all are consecutive)
(x-1) + x + (x+1) = 108
3x = 108
x = 36
Obviously you could have set x. the 1st; x+1 the 2nd & x+2 the 3rd & you would reach the same result x =36