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Which quadratic function has one real solution?

0 = 2(x + 7)(x – 5)
0 = (x – 3)(x – 3)
0 = 2.4(x – 2)(x + 2)
0 = (x – 2)(x – 1)

Respuesta :

meerkat18
A quadratic equation could yield one of two types of roots: real and imaginary. Rational roots are whole numbers and fractions, whereas imaginary roots are complex numbers incorporating the 'i' symbol. When you say, the equation has one real root, this means that there are actually two roots but same in value. That would be letter (x-3)(x-3) = 0. Its root is x=3.
abidemiokin

The quadratic equation has a leading degree of 2.The quadratic function that has one real solution is 0 = (x – 3)(x – 3)

How to find the solution to a quadratic equation

The quadratic equation has a leading degree of 2.


From the given question, we are to find the quadratic function that has one real solution.

The required quadratic function must have the same factor. From the given equations, only the expression 0 = (x – 3)(x – 3) has one factor which is (x-3).

Hence the quadratic function that has one real solution is 0 = (x – 3)(x – 3)

Learn more on quadratic equation here: https://brainly.com/question/1214333

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